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252

10 Room Acoustics and Acoustical Partitions

below.

Also, another formula for calculating the same transmission loss

(TL) through a partition wall will be derived and is summarized as follows:

 

 

1

 

TL Lwi Lwt ¼

10 log

 

 

τ

wt

 

 

 

τ

 

 

 

 

wi

 

 

 

where τ is the transmission coefcient, wi is the incident sound power, and wt is the transmitted sound power.

Section 10.5 introduces noise reduction (NR) due to acoustical partitions. A formula that relates the noise reduction (NR) to the sound pressure level near the wall in Room 1 (Lp1 ) and sound pressure level near the wall in Room 2 (Lp2 ) will be dened and is summarized below. Also, a formula for calculating sound pressure level due to a sound source through a partition wall will be derived and is summarized as follows:

NR ¼ Lp1 Lp2

1

 

Swall

 

LP ¼ Lp,wall þ 10 log

 

þ

 

 

4

R

where Lp, wall is the sound pressure level (SPL) near the wall without considering the reection wave and LP is the SPL near the wall considering both the direct and reected waves:

source

10.1Sound Power, Acoustic Intensity, and Energy Density

10.1.1 Definition of Sound Power

The sound power w is dened as the energy per unit time and can be formulated in terms of the RMS pressure PRMS, the RMS velocity VRMS, and an area S as:

10.1 Sound Power, Acoustic Intensity, and Energy Density

253

w ¼ PRMSVRMSS

And the units in the MKS system are:

whJs i ¼ PhmN2i V hms i S m2

For plane waves moving at the speed of sound c, because VRMS ¼ PRMS, the sound

ρoc

power is:

P2

w ¼ RMS S ðplane wavesÞ

ρoc

Remarks

The sound power of an acoustic source is the energy of an enclosed surface of the acoustic source.

10.1.2 Definition of Acoustic Intensity

The acoustic intensity I is dened as the energy per unit time per unit area or (by the denition of sound power) the sound power w per unit area S as:

I wS

Based on the denition of sound power w, acoustic intensity I can be formulated in terms of the RMS pressure PRMS and the RMS velocity VRMS as:

I ¼ w ¼ PRMSVRMSS ¼ PRMSVRMS

S S

And the units in the MKS system are:

 

J

 

N

 

m

Ih

 

i

¼ Ph

 

i

V h

 

i

sm2

m2

s

For plane waves moving at the speed of sound c, because VRMS ¼ PRMS as shown

ρoc

in Chap. 4, the acoustic intensity is:

P2

I ¼ RMS ðplane wavesÞ

ρoc

254

10 Room Acoustics and Acoustical Partitions

10.1.3 Definition of Energy Density

The energy density δ is dened as the energy per unit volume and can be formulated in terms of sound power w (energy per unit time) as:

δ cSw

Based on the denition of sound power w, energy density δ can be formulated in terms of the RMS pressure PRMS and the RMS velocity VRMS as:

δ ¼

w

 

PRMSVRMSS

1

 

¼

 

¼ PRMSVRMS

 

cS

cS

c

And the units in the MKS system are:

 

J

 

N

 

m

 

1 s

δh

 

i

¼ Ph

 

i

V h

 

i

 

 

hmi

m3

m2

s

c

For plane waves moving at the speed of sound c, because VRMS ¼ PRMS as shown

ρoc

in Chap. 4, the acoustic intensity is:

P2

δ ¼ RMS ðplane wavesÞ

ρoc2

Note that the acoustic intensity is useful for deriving formulas for room acoustics because it is dened as the energy per unit volume and can be formulated based on the conservation of energy.

10.2Absorption Coefcients, Room Constant, and Reverberation Time

10.2.1 Absorption Coefficient of Surface

The statistical absorption coefcient or random incidence sound absorption coef- cient, α, is frequency-dependent and is dened as the ratio of acoustic energy absorbed by a surface to the acoustical energy incident upon the surface when the

incident sound eld is perfectly diffused, α wi wr .

wi

The absorption coefcient of a material is a number between 0 and 1 that indicates the proportion of sound which is absorbed by the surface compared to the incident sound. A large, fully open window would offer no reection, as any sound reaching it would pass straight out and no sound would be reected. This would have an

10.2 Absorption Coefcients, Room Constant, and Reverberation Time

255

absorption coefcient of 1. Conversely, a thick, smooth painted concrete ceiling would be the acoustic equivalent of a mirror and have an absorption coefcient very close to 0.

Sound absorption coefcients of common materials used in buildings are presented in the table below.

Table: Absorption coefcients of general building materials

 

 

Octave band center frequency [Hz]

 

 

 

 

 

 

 

 

 

Materials

Descriptions

125

250

500

1000

2000

4000

 

 

 

 

 

 

 

 

Brick

Smooth, painted or glazed

0.01

0.01

0.02

0.02

0.02

0.03

 

 

 

 

 

 

 

 

Brick

Course surface

0.03

0.03

0.03

0.04

0.05

0.07

 

 

 

 

 

 

 

 

Concrete

Smooth, painted, or glazed

0.01

0.01

0.02

0.02

0.02

0.02

Concrete

Smooth, unpainted

0.01

0.01

0.02

0.02

0.03

0.05

Concrete

Coarse

0.01

0.02

0.04

0.06

0.08

0.10

 

 

 

 

 

 

 

 

Marble

Floor

0.01

0.01

0.01

0.02

0.02

0.02

 

 

 

 

 

 

 

 

Wood

Hardwood oor

0.15

0.10

0.06

0.08

0.10

0.10

Wood

Thin plywood

0.40

0.20

0.10

0.08

0.06

0.06

Carpet

Thin carpet, on concrete

0.10

0.15

0.25

0.30

0.33

0.30

 

 

 

 

 

 

 

 

Carpet

Thin carpet, on foam rubber

0.20

0.25

0.30

0.30

0.33

0.30

 

 

 

 

 

 

 

 

Carpet

Heavy carpet, on concrete

0.02

0.06

0.14

0.37

0.60

0.65

Carpet

Heavy carpet, on foam rubber

0.08

0.24

0.57

0.69

0.71

0.73

Glass

Normal window

0.35

0.25

0.18

0.12

0.07

0.04

 

 

 

 

 

 

 

 

Glass

Large window

0.30

0.10

0.05

0.12

0.07

0.04

Water

Swimming pool surface

0.01

0.01

0.01

0.01

0.02

0.03

Since different surfaces of a room will, in general, have different absorption coefcients, an average sound absorption coefcient α need be calculated for a given room:

n

P Siαi α ¼ i¼1n

P

Si

i¼1

where:

Si¼ area of the i-th surface.

αi¼ absorption coefcient at the i-th surface.

Excess Absorption Coefcient Due to Air

For large rooms and frequencies above 2000 Hz, air absorption (not including surface absorption) may become signicant. The absorption due to air in the room is represented by the excess absorption coefcient and is given by:

256

 

 

10 Room Acoustics and Acoustical Partitions

αex ¼ kD ¼ k S

¼ k

Length

4S

 

Area

 

 

4V

 

1

 

V

 

Volume

 

k¼ experimentally determined coefcient of air (see table below) D ¼ 4SV (distance between ceiling and oor)

V¼ volume of the room S¼ total surface area

where D is the average traveling distance between ceiling and oor. The formula D is based on a half cube of 10 [m] by 10 [m] by 5 [m] as shown below:

The distance between ceiling and loor

Half Cube

4 × 5 × 10 × 10

2 × 10 × 10 + 4 × 5 × 10

=

where

= 400

10

 

 

 

 

 

The total average absorption coefcient then becomes:

α0 ¼ αtot ¼ α þ αex

Approximate values for the coefcient k in metric units [3]

 

 

Frequency [Hz]

 

 

 

 

2000

 

4000

8000

Relative humidity [%]

Temperature [C]

k [1/m]

 

k [1/m]

k [1/m]

 

 

 

 

 

 

30

20

0.0030

 

0.0095

0.0340

30

25

0.0029

 

0.0078

 

30

30

0.0028

 

0.0070

 

 

 

 

 

 

 

50

20

0.0024

 

0.0061

0.0215

 

 

 

 

 

 

50

25

0.0024

 

0.0059

 

50

30

0.0023

 

0.0058

 

70

20

0.0021

 

0.0053

0.0150

 

 

 

 

 

 

70

25

0.0021

 

0.0053

 

 

 

 

 

 

 

70

30

0.0021

 

0.0052