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34

2 Derivation of Acoustic Wave Equation

2.3Equation of State

The third equation needed for deriving the acoustic wave equation is called the equation of state which is the most difcult equation to derive and comprehend among the three equations. This is because it involves both the kinetic theory of gases and the principle of conservation of energy. Despite this difculty, the physics involved in the equation of state is both interesting and important for understanding acoustics.

The equation of state describes the relationship between air pressure change and mass density change as shown in the gure below:

Pressure:

 

 

 

Equation of State

 

 

 

Density:

 

 

 

=

1

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

: Absolute density

: Averaged density

: Absolute pressure

Pressure:

 

: Averaged pressure

Density:

 

 

 

 

 

 

The equation of state can be expressed as:

P Po

¼

γ

ρ ρo

Po

 

ρo

where:

Po is the average air pressure. P is the instantaneous pressure.

ρo is the averaged air mass density. ρ is the instantaneous mass density.

γis the ratio of specic heats and is dened as:

γ3α þ 2 3α

where α is a ratio between the total energy (rotational energy + translational energy) and the translational energy of molecules as:

2.3 Equation of State

 

35

α

 

21 Iaθca2 þ 21 mavca2

 

 

21 mavca2

 

or:

12 Iaθ2ca ¼ ðα 1Þ 12 mav2ca

where ma is the mass of a particle, Ica is the mass moment of inertia, vca is the collision speed, and θca is the spin speed of a particle.

The equation of state can be derived from (A) the law of conservation of energy and (B) pressure due to the kinetic theory of gases.

The following is a owchart of the derivation of the equation of state:

Derivation of Equation of State

A 2

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

=

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

Energy

 

 

 

Work

 

 

 

 

 

 

 

 

 

 

 

 

Increase

 

 

 

Done

 

 

 

 

 

 

 

 

 

 

 

 

= 0

 

 

 

 

 

 

 

 

 

 

 

 

=

 

 

 

 

 

 

 

 

2

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

B

=

1

= −

3

Colliding Pressure

the same

=

1

= −

 

3

 

2.3.1Energy Increase due to Work Done

The energy of a particle with mass ma occupying a volume Va is the summation of translational and rotational energy:

Ka ¼ 12 mav2ca þ 12 Iaθ2ca

Assume the rotational kinetic energy is linearly related to the translational kinetic energy:

36

2 Derivation of Acoustic Wave Equation

12 Iaθ2ca ¼ ðα 1Þ 12 mav2ca

where α is equal to or greater than 1. When the particle does not have rotational energy, α¼1; when the particle has rotational energy, α >1:

Kinetic Energy Considering

 

 

 

 

 

 

 

Kinetic energy (

)

 

Rotation of Air Particle

 

 

1

 

1

 

̇

 

 

 

 

 

 

 

 

= 2

+

2

 

 

 

 

=

̇

 

1

 

Colliding Pressure:

=

 

 

1

 

 

 

=

 

3

 

 

 

 

 

 

3

 

 

 

 

 

 

Using this linear relationship between rotational energy and translational energy, the total energy of a particle is given as follows:

Ka ¼ 12 mav2ca þ 12 Iaθ2ca ¼ 12 mav2ca þ ðα 1Þ 12 mav2ca ¼ α2 mav2ca

According to the conservation of energy, in a closed system, the increase of energy is equal to the work done to the system:

∆ =

 

 

 

= −

2

 

 

 

 

 

 

 

 

Energy

 

Work

 

 

Increase

 

Done

 

 

 

 

 

The total energy Ka includes both translational energy and rotational energy and is equal to α2 mav2ca , as shown before. And the work done by a constant external pressure Po due to a system of decreased volume dVa is PodVa; therefore:

Ka ¼ W

!α2 d mav2ca ¼ PodVa

2.3 Equation of State

37

2.3.2Pressure due to Colliding of Gases

According to the kinetic theory, the pressure is directly related to the translational energy and is independent of the rotational energy. The pressure due to the particle collision is:

Po ¼ 1 ma v2

3 Va ca

The derivation of the collision pressure is based on the fundamentals of kinetic energy, as shown in the gure below:

Colliding Pressure (Kinetic theory of gases)

1 = 3

4 = 3

According to Newtons law of motion, the force is equal to the change of momentum when the particle collides with the wall of the sphere as:

Fa

 

ðmavcaÞ

2mavca

mavca2

 

 

 

 

 

¼

¼ vcaa

¼

Ra

 

t

 

 

 

 

2R

 

 

 

The pressure on the surface of the sphere is the force divided by the total surface area of the sphere as:

2

Fa

 

mavca

 

1 ma 2

 

 

Ra

 

 

Po ¼

 

¼

 

 

 

¼

 

 

 

 

vca

Sa

4πRa2

3

Va

Note that the pressure is directly related to the translational energy only (not include the rotational energy), and rewrite the relation as: