- •Study Skills Workshop
- •1.1 An Introduction to the Whole Numbers
- •1.2 Adding Whole Numbers
- •1.3 Subtracting Whole Numbers
- •1.4 Multiplying Whole Numbers
- •1.5 Dividing Whole Numbers
- •1.6 Problem Solving
- •1.7 Prime Factors and Exponents
- •1.8 The Least Common Multiple and the Greatest Common Factor
- •1.9 Order of Operations
- •THINK IT THROUGH Education Pays
- •2.1 An Introduction to the Integers
- •THINK IT THROUGH Credit Card Debt
- •2.2 Adding Integers
- •THINK IT THROUGH Cash Flow
- •2.3 Subtracting Integers
- •2.4 Multiplying Integers
- •2.5 Dividing Integers
- •2.6 Order of Operations and Estimation
- •Cumulative Review
- •3.1 An Introduction to Fractions
- •3.2 Multiplying Fractions
- •3.3 Dividing Fractions
- •3.4 Adding and Subtracting Fractions
- •THINK IT THROUGH Budgets
- •3.5 Multiplying and Dividing Mixed Numbers
- •3.6 Adding and Subtracting Mixed Numbers
- •THINK IT THROUGH
- •3.7 Order of Operations and Complex Fractions
- •Cumulative Review
- •4.1 An Introduction to Decimals
- •4.2 Adding and Subtracting Decimals
- •4.3 Multiplying Decimals
- •THINK IT THROUGH Overtime
- •4.4 Dividing Decimals
- •THINK IT THROUGH GPA
- •4.5 Fractions and Decimals
- •4.6 Square Roots
- •Cumulative Review
- •5.1 Ratios
- •5.2 Proportions
- •5.3 American Units of Measurement
- •5.4 Metric Units of Measurement
- •5.5 Converting between American and Metric Units
- •Cumulative Review
- •6.2 Solving Percent Problems Using Percent Equations and Proportions
- •6.3 Applications of Percent
- •6.4 Estimation with Percent
- •6.5 Interest
- •Cumulative Review
- •7.1 Reading Graphs and Tables
- •THINK IT THROUGH The Value of an Education
- •Cumulative Review
- •8.1 The Language of Algebra
- •8.2 Simplifying Algebraic Expressions
- •8.3 Solving Equations Using Properties of Equality
- •8.4 More about Solving Equations
- •8.5 Using Equations to Solve Application Problems
- •8.6 Multiplication Rules for Exponents
- •Cumulative Review
- •9.1 Basic Geometric Figures; Angles
- •9.2 Parallel and Perpendicular Lines
- •9.3 Triangles
- •9.4 The Pythagorean Theorem
- •9.5 Congruent Triangles and Similar Triangles
- •9.6 Quadrilaterals and Other Polygons
- •9.7 Perimeters and Areas of Polygons
- •THINK IT THROUGH Dorm Rooms
- •9.8 Circles
- •9.9 Volume
- •Cumulative Review
754 |
Chapter 9 An Introduction to Geometry |
Objectives
1Identify corresponding parts of congruent triangles.
2Use congruence properties to prove that two triangles are congruent.
3Determine whether two triangles are similar.
4Use similar triangles to find unknown lengths in application problems.
© iStockphoto.com/Lucinda Deitman
S E C T I O N 9.5
Congruent Triangles and Similar Triangles
In our everyday lives, we see many types of triangles.Triangular-shaped kites, sails, roofs, tortilla chips, and ramps are just a few examples. In this section, we will discuss how to compare the size and shape of two given triangles. From this comparison, we can make observations about their side lengths and angle measures.
1 Identify corresponding parts of congruent triangles.
Simply put, two geometric figures are congruent if they have the same shape and size. For example, if ABC and DEF shown below are congruent, we can write
ABC DEF Read as “Triangle ABC is congruent to triangle DEF.”
C F
A B D E
One way to determine whether two triangles are congruent is to see if one triangle can be moved onto the other triangle in such a way that it fits exactly. When we writeABC DEF, we are showing how the vertices of one triangle are matched to the vertices of the other triangle to obtain a “perfect fit.”We call this matching of points a correspondence.
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ABC DEF |
A 4 D Read as “Point A corresponds to point D.”
B 4 E Read as “Point B corresponds to point E.”
C 4 F Read as “Point C corresponds to point F.”
When we establish a correspondence between the vertices of two congruent triangles, we also establish a correspondence between the angles and the sides of the triangles. Corresponding angles and corresponding sides of congruent triangles are called corresponding parts. Corresponding parts of congruent triangles are always congruent. That is, corresponding parts of congruent triangles always have the same measure. For the congruent triangles shown above, we have
m( A) m( D) |
m( B) m( E) |
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m( C) m( F)
m(AB) m(DE)
Congruent Triangles
Two triangles are congruent if and only if their vertices can be matched so that the corresponding sides and the corresponding angles are congruent.
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EXAMPLE 1 |
Refer to the figure below, where XYZ PQR. |
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a. Name the six congruent corresponding parts |
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9.5 Congruent Triangles and Similar Triangles |
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Strategy We will establish the correspondence between the vertices of XYZ and the vertices of PQR.
WHY This will, in turn, establish a correspondence between the congruent corresponding angles and sides of the triangles.
Solution
a. The correspondence between the vertices is
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XYZ PQR |
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X 4 P Y 4 Q |
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Corresponding parts of congruent triangles are congruent. Therefore, the congruent corresponding angles are
X P Y Q Z R
The congruent corresponding sides are
YZ QR XZ PR XY PQ
b.From the figure, we see that m( X) 27°. Since X P, it follows that m( P) 27°.
c.From the figure, we see that m(PR) 11 inches. Since XZ PR, it follows
that m(XZ) 11 inches.
2Use congruence properties to prove that two triangles are congruent.
Sometimes it is possible to conclude that two triangles are congruent without having to show that three pairs of corresponding angles are congruent and three pairs of corresponding sides are congruent.To do so, we apply one of the following properties.
SSS Property
If three sides of one triangle are congruent to three sides of a second triangle, the triangles are congruent.
We can show that the triangles shown below are congruent by the SSS property:
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CD ST Since m(CD) 3 and m(ST) 3, the segments are congruent.
DE TR Since m(DE) 4 and m(TR) 4, the segments are congruent.
EC RS Since m(EC) 5 and m(RS) 5, the segments are congruent.
Therefore, CDE STR.
Self Check 1
Refer to the figure below, where
ABC EDF.
a.Name the six congruent corresponding parts of the triangles.
b.Find m( C).
c.Find m(FE).
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3 ft |
7 ft |
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110° |
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Now Try Problem 33
SAS Property
If two sides and the angle between them in one triangle are congruent, respectively, to two sides and the angle between them in a second triangle, the triangles are congruent.
756 |
Chapter 9 An Introduction to Geometry |
We can show that the triangles shown below are congruent by the SAS property:
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TV FG Since m(TV) 2 and m(FG) 2, the segments are congruent.
V G Since m( V) 90° and m( G) 90°, the angles are congruent.
UV EG Since m(UV) 3 and m(EG) 3, the segments are congruent.
Therefore, TVU FGE.
ASA Property
If two angles and the side between them in one triangle are congruent, respectively, to two angles and the side between them in a second triangle, the triangles are congruent.
We can show that the triangles shown below are congruent by the ASA property:
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P B Since m( P) 60° and m( B) 60°, the angles are congruent.
PR BC Since m(PR) 9 and m(BC) 9, the segments are congruent.
R C Since m( R) 82° and m( C) 82°, the angles are congruent.
Therefore, PQR BAC.
Caution! There is no SSA property. To illustrate this, consider the triangles shown below. Two sides and an angle of ABC are congruent to two sides and an angle of DEF. But the congruent angle is not between the congruent sides.
We refer to this situation as SSA. Obviously, the triangles are not congruent because they are not the same shape and size.
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EXAMPLE 2 Explain why the triangles in the figure on the following page are congruent.
Strategy We will show that two sides and the angle between them in one triangle are congruent, respectively, to two sides and the angle between them in a second triangle.
9.5 Congruent Triangles and Similar Triangles |
757 |
WHY Then we know that the two triangles are congruent by the SAS property.
Solution Since vertical angles are congruent,
1 2
From the figure, we see that
AC EC and BC DC
Since two sides and the angle between them in one triangle are congruent, respectively, to two sides and the angle between them in a second triangle,ABC EDC by the SAS property.
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C 5 cm |
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EXAMPLE 3 Are RST and RUT in the figure on the right congruent?
Strategy We will show that two angles and the side between them in one triangle are congruent, respectively, to two angles and the
side between them in a second triangle.
R
WHY Then we know that the two triangles are congruent by the ASA property.
Solution From the markings on the figure, we know that two pairs of angles are congruent.
SRT URT These angles are marked with 1 tick mark, which indicates that they have the same measure.
STR UTR These angles are marked with 2 tick marks, which indicates that they have the same measure.
S
T
U
From the figure, we see that the triangles have side RT in common. Furthermore, RT is between each pair of congruent angles listed above. Since every segment is congruent to itself, we also have
RT RT
Knowing that two angles and the side between them in RST are congruent, respectively, to two angles and the side between them in RUT, we can conclude that RST RUT by the ASA property.
3 Determine whether two triangles are similar.
We have seen that congruent triangles have the same shape and size. Similar triangles have the same shape, but not necessarily the same size. That is, one triangle is an exact scale model of the other triangle. If the triangles in the figure below are similar, we can write ABC DEF (read the symbol as “is similar to”).
C
F
Self Check 2
Are the triangles in the figure below congruent? Explain why or why not.
C
A
B
D
E
Now Try Problem 35
Self Check 3
Are the triangles in the following figure congruent? Explain why or why not.
R
T
Q S
Now Try Problem 37
A B D E
Success Tip Note that congruent triangles are always similar, but similar triangles are not always congruent.
758 |
Chapter 9 An Introduction to Geometry |
Self Check 4
If GEF IJH, name the congruent angles and the sides that are proportional.
G E J I
H
F
Now Try Problem 39
The formal definition of similar triangles requires that we establish a correspondence between the vertices of the triangles. The definition also involves the word proportional.
Recall that a proportion is a mathematical statement that two ratios (fractions) are equal. An example of a proportion is
12 48
In this case, we say that 12 and 48 are proportional.
Similar Triangles
Two triangles are similar if and only if their vertices can be matched so that corresponding angles are congruent and the lengths of corresponding sides are proportional.
Refer to the figure below. If PQR CDE, name the congruent angles and the sides that are proportional.
C
P
Q R D E
Strategy We will establish the correspondence between the vertices of PQR and the vertices of CDE.
WHY This will, in turn, establish a correspondence between the congruent corresponding angles and proportional sides of the triangles.
Solution When we write PQR CDE,a correspondence between the vertices of the triangles is established.
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PQR CDE |
Since the triangles are similar, corresponding angles are congruent:
P C Q D R E
The lengths of the corresponding sides are proportional. To simplify the notation, we will now let PQ m(PQ), CD m(CD), QR m(QR), and so on.
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Written in a more compact way, we have
CDPQ QRDE CEPR
Property of Similar Triangles
If two triangles are similar, all pairs of corresponding sides are in proportion.
9.5 Congruent Triangles and Similar Triangles |
759 |
It is possible to conclude that two triangles are similar without having to show that all three pairs of corresponding angles are congruent and that the lengths of all three pairs of corresponding sides are proportional.
AAA Similarity Theorem
If the angles of one triangle are congruent to corresponding angles of another triangle, the triangles are similar.
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EXAMPLE 5 |
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In the figure on the right, PR MN. Are PQR and NQM |
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Strategy We will show that the angles of P |
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WHY Then we know that the two triangles
are similar by the AAA property.
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Solution Since vertical angles are congruent,
PQR NQM This is one pair of congruent corresponding angles.
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In the figure, we can view PN as a transversal cutting parallel line segments PR and MN. Since alternate interior angles are then congruent, we have:
RPQ MNQ This is a second pair of congruent corresponding angles.
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Furthermore, we can view RM as a transversal cutting parallel line segments PR and MN. Since alternate interior angles are then congruent, we have:
QRP QMN This is a third pair of congruent corresponding angles.
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EXAMPLE 6 |
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Strategy To find x, we will write a |
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Solution
a.When we write RST JKL, a correspondence between the vertices of the two triangles is established.
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Self Check 5
In the figure below, YA ZB. Are XYA and XZB similar triangles?
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Now Try Problems 41 and 43
Self Check 6
In the figure below,
DEF GHI. Find:
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760 |
Chapter 9 An Introduction to Geometry |
The lengths of corresponding sides of these similar triangles are proportional.
RTJL KLST
4832 20x
48(20) 32x
960 32x
30 x
Thus, x is 30.
Each fraction is a ratio of a side length of RST to its corresponding side length of JKL.
Substitute: RT 48, JL 32, ST x, and KL 20.
Find each cross product and set them equal.
Do the multiplication.
To isolate x, undo the multiplication by 32 by dividing both sides by 32.
4820 960
30
32 960
96
00
00
0
b.To find y, we write a proportion of corresponding side lengths in such a way that y is the only unknown.
RTJL RSJK
4832 36y
48y 32(36)
48y 1,152 y 24
Thus, y is 24.
Substitute: RT 48, JL 32, RS 36, and JK y.
Find each cross product and set them equal.
Do the multiplication.
To isolate y, undo the multiplication by 48 by dividing both sides by 48.
36
24
32
48 1,152
72
96
1080
192
1152
192 0
Self Check 7
In the figure below,
ABC EDC. Find h.
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E
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25 ft
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Now Try Problem 85
4Use similar triangles to find unknown lengths in application problems.
Similar triangles and proportions can be used to find lengths that would normally be difficult to measure. For example, we can use the reflective properties of a mirror to calculate the height of a flagpole while standing safely on the ground.
To determine the height of a flagpole, a woman walks to a point 20 feet from its base, as shown below.Then she takes a mirror from her purse, places it on the ground, and walks 2 feet farther away, where she can see the top of the pole reflected in the mirror. Find the height of the pole.
D
The woman’s eye level is 5 feet from the ground.
B
h
5 ft
C
E A 2 ft 20 ft
Strategy We will show that ABC EDC.
WHY Then we can write a proportion of corresponding sides so that h is the only unknown and we can solve the proportion for h.
Solution To show that ABC EDC, we begin by applying an important fact about mirrors.When a beam of light strikes a mirror, it is reflected at the same angle as it hits the mirror. Therefore, BCA DCE. Furthermore, A E because the woman and the flagpole are perpendicular to the ground. Finally, if two pairs of
9.5 Congruent Triangles and Similar Triangles |
761 |
corresponding angles are congruent, it follows that the third pair of corresponding angles are also congruent: B D. By the AAA similarity theorem, we conclude that ABC EDC.
Since the triangles are similar, the lengths of their corresponding sides are in proportion. If we let h represent the height of the flagpole, we can find h by solving the following proportion.
Height of the flagpole
Height of the woman
h
5
2h
2h h
20
2
5(20)
100
50
Distance from flagpole to mirror
Distance from woman to mirror
Find each cross product and set them equal.
Do the multiplication.
To isolate h, divide both sides by 2.
The flagpole is 50 feet tall.
ANSWERS TO SELF CHECKS |
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X X, XYA XZB, XAY XBZ 6. a. 6 |
b. 11.25 7. 500 ft |
S E C T I O N 9.5 STUDY SET
VOCABULARY
Fill in the blanks.
1.triangles are the same size and the same
shape.
2.When we match the vertices of ABC with the vertices of DEF, as shown below, we call this
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CONCEPTS
7. Refer to the triangles below.
a.Do these triangles appear to be congruent? Explain why or why not.
b.Do these triangles appear to be similar? Explain why or why not.
8.a. Draw a triangle that is
congruent to CDE shown below. Label it
ABC.
b.Draw a triangle that is similar to, but not congruent to,CDE. Label it MNO.
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D
Fill in the blanks.
9. XYZ
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762Chapter 9 An Introduction to Geometry
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13.Name the six corresponding parts of the congruent triangles shown below.
Y T
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14.Name the six corresponding parts of the congruent triangles shown below.
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Fill in the blanks.
23.Two triangles are similar if and only if their vertices can be matched so that corresponding angles are congruent and the lengths of corresponding sides are
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24.If the angles of one triangle are congruent to corresponding angles of another triangle, the triangles
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For certain application problems, similar triangles and |
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NOTATION
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The symbol is read as “ |
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The symbol is read as “ |
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29.Use tick marks to show the congruent parts of the triangles shown below.
K H KR HJ M E
K M H E
R J
30.Use tick marks to show the congruent parts of the triangles shown below.
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GUIDED PRACTICE
Name the six corresponding parts of the congruent triangles.
See Objective 1.
C F
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33.Refer to the figure below, where BCD MNO.
a.Name the six congruent corresponding parts of the triangles. See Example 1.
b.Find m( N).
c.Find m(MO).
d.Find m(CD).
C
N
72°
9 ft
49°
B D O M
10 ft
34. Refer to the figure below, where DCG RST.
a. Name the six congruent corresponding parts of the triangles. See Example 1.
b. Find m( R). c. Find m(DG). d. Find m(ST).
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3 in. |
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9.5 Congruent Triangles and Similar Triangles |
763 |
Determine whether each pair of triangles is congruent. If they are, tell why. See Examples 2 and 3.
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37. 38.
6 m
6m
39.Refer to the similar triangles shown below.
See Example 4.
a.Name 3 pairs of congruent angles.
b.Complete each proportion.
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c.We can write the answer to part b in a more compact form:
LM MR HE
L R H E
M
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40.Refer to the similar triangles shown below.
See Example 4.
a.Name 3 pairs of congruent angles.
b.Complete each proportion.
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c.We can write the answer to part b in a more compact form:
DF YX WX
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Y F W D
764 |
Chapter 9 An Introduction to Geometry |
Tell whether the triangles are similar. See Example 5.
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43. 44.
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70° |
40° |
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47. 48.
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51. 52.
In Problems 53 and 54, MSN TPR. Find x and y.
See Example 6.
53.S
P
y
28 10 x
M 21 N T 6 R
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TRY IT YOURSELF
Tell whether each statement is true. If a statement is false, tell why.
57.If three sides of one triangle are the same length as the corresponding three sides of a second triangle, the triangles are congruent.
58.If two sides of one triangle are the same length as two sides of a second triangle, the triangles are congruent.
59.If two sides and an angle of one triangle are congruent, respectively, to two sides and an angle of a second triangle, the triangles are congruent.
60.If two angles and the side between them in one triangle are congruent, respectively, to two angles and the side between them in a second triangle, the triangles are congruent.
Determine whether each pair of triangles are congruent. If they are, tell why.
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40° |
40°
63. 64.
40° |
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6 yd |
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67. 68.
In Problems 69 and 70, ABC DEF. Find x and y.
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In Problems 71 and 72, find x and y. |
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71. |
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72. |
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In Problems 73–76, find x. |
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74. |
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9.5 |
Congruent Triangles and Similar Triangles |
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7 in. |
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77.If DE in the figure below is parallel to AB, ABC will be similar to DEC. Find x.
C
x
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78.If SU in the figure below is parallel to TV, SRU will be similar to TRV. Find x.
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79.If DE in the figure below is parallel to CB, EAD will be similar to BAC. Find x.
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80.If HK in the figure below is parallel to AB, HCK will be similar to ACB. Find x.
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766 |
Chapter 9 An Introduction to Geometry |
APPLICATIONS
81.SEWING The pattern that is sewn on the rear
pocket of a pair of blue jeans is shown below. IfAOB COD, how long is the stitching from
point A to point D?
A C
9.5 cm
O
8 cm
BD
82.CAMPING The base of the tent pole is placed at the midpoint between the stake at point A and the stake
at point B, and it is perpendicular to the ground, as shown below. Explain why ACD BCD.
84.HEIGHT OF A BUILDING A man places a mirror on the ground and sees the reflection of the top of a building, as shown below. Find the height of the building.
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85.HEIGHT OF A TREE The tree shown below casts a shadow 24 feet long when a man 6 feet tall casts a shadow 4 feet long. Find the height of the tree.
C
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83. A surveying crew needs to |
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shown in the illustration |
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below. Because of a |
Laska |
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dangerous current, they |
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iStockphoto.com/Lukaz |
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decide to stay on the west |
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side of the river and use |
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geometry to find its width. |
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Their approach is to create |
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two similar right triangles on
dry land. Then they write and solve a proportion to find w. What is the width of the river?
20 ft |
25 ft |
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74 ft
West East w ft
h
6 ft
4 ft |
24 ft |
86.WASHINGTON, D.C. The Washington Monument
casts a shadow of 16612 feet at the same time as a 5-foot-tall tourist casts a shadow of 112 feet. Find the height of the monument.
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