- •Preface
- •Contents
- •1 Introduction
- •1.1 Physics
- •1.2 Mechanics
- •1.3 Integrating Numerical Methods
- •1.4 Problems and Exercises
- •1.5 How to Learn Physics
- •1.5.1 Advice for How to Succeed
- •1.6 How to Use This Book
- •2 Getting Started with Programming
- •2.1 A Python Calculator
- •2.2 Scripts and Functions
- •2.3 Plotting Data-Sets
- •2.4 Plotting a Function
- •2.5 Random Numbers
- •2.6 Conditions
- •2.7 Reading Real Data
- •2.7.1 Example: Plot of Function and Derivative
- •3 Units and Measurement
- •3.1 Standardized Units
- •3.2 Changing Units
- •3.4 Numerical Representation
- •4 Motion in One Dimension
- •4.1 Description of Motion
- •4.1.1 Example: Motion of a Falling Tennis Ball
- •4.2 Calculation of Motion
- •4.2.1 Example: Modeling the Motion of a Falling Tennis Ball
- •5 Forces in One Dimension
- •5.1 What Is a Force?
- •5.2 Identifying Forces
- •5.3.1 Example: Acceleration and Forces on a Lunar Lander
- •5.4 Force Models
- •5.5 Force Model: Gravitational Force
- •5.6 Force Model: Viscous Force
- •5.6.1 Example: Falling Raindrops
- •5.7 Force Model: Spring Force
- •5.7.1 Example: Motion of a Hanging Block
- •5.9.1 Example: Weight in an Elevator
- •6 Motion in Two and Three Dimensions
- •6.1 Vectors
- •6.2 Description of Motion
- •6.2.1 Example: Mars Express
- •6.3 Calculation of Motion
- •6.3.1 Example: Feather in the Wind
- •6.4 Frames of Reference
- •6.4.1 Example: Motion of a Boat on a Flowing River
- •7 Forces in Two and Three Dimensions
- •7.1 Identifying Forces
- •7.3.1 Example: Motion of a Ball with Gravity
- •7.4.1 Example: Path Through a Tornado
- •7.5.1 Example: Motion of a Bouncing Ball with Air Resistance
- •7.6.1 Example: Comet Trajectory
- •8 Constrained Motion
- •8.1 Linear Motion
- •8.2 Curved Motion
- •8.2.1 Example: Acceleration of a Matchbox Car
- •8.2.2 Example: Acceleration of a Rotating Rod
- •8.2.3 Example: Normal Acceleration in Circular Motion
- •9 Forces and Constrained Motion
- •9.1 Linear Constraints
- •9.1.1 Example: A Bead in the Wind
- •9.2.1 Example: Static Friction Forces
- •9.2.2 Example: Dynamic Friction of a Block Sliding up a Hill
- •9.2.3 Example: Oscillations During an Earthquake
- •9.3 Circular Motion
- •9.3.1 Example: A Car Driving Through a Curve
- •9.3.2 Example: Pendulum with Air Resistance
- •10 Work
- •10.1 Integration Methods
- •10.2 Work-Energy Theorem
- •10.3 Work Done by One-Dimensional Force Models
- •10.3.1 Example: Jumping from the Roof
- •10.3.2 Example: Stopping in a Cushion
- •10.4.1 Example: Work of Gravity
- •10.4.2 Example: Roller-Coaster Motion
- •10.4.3 Example: Work on a Block Sliding Down a Plane
- •10.5 Power
- •10.5.1 Example: Power Exerted When Climbing the Stairs
- •10.5.2 Example: Power of Small Bacterium
- •11 Energy
- •11.1 Motivating Examples
- •11.2 Potential Energy in One Dimension
- •11.2.1 Example: Falling Faster
- •11.2.2 Example: Roller-Coaster Motion
- •11.2.3 Example: Pendulum
- •11.2.4 Example: Spring Cannon
- •11.3 Energy Diagrams
- •11.3.1 Example: Energy Diagram for the Vertical Bow-Shot
- •11.3.2 Example: Atomic Motion Along a Surface
- •11.4 The Energy Principle
- •11.4.1 Example: Lift and Release
- •11.4.2 Example: Sliding Block
- •11.5 Potential Energy in Three Dimensions
- •11.5.1 Example: Constant Gravity in Three Dimensions
- •11.5.2 Example: Gravity in Three Dimensions
- •11.5.3 Example: Non-conservative Force Field
- •11.6 Energy Conservation as a Test of Numerical Solutions
- •12 Momentum, Impulse, and Collisions
- •12.2 Translational Momentum
- •12.3 Impulse and Change in Momentum
- •12.3.1 Example: Ball Colliding with Wall
- •12.3.2 Example: Hitting a Tennis Ball
- •12.4 Isolated Systems and Conservation of Momentum
- •12.5 Collisions
- •12.5.1 Example: Ballistic Pendulum
- •12.5.2 Example: Super-Ball
- •12.6 Modeling and Visualization of Collisions
- •12.7 Rocket Equation
- •12.7.1 Example: Adding Mass to a Railway Car
- •12.7.2 Example: Rocket with Diminishing Mass
- •13 Multiparticle Systems
- •13.1 Motion of a Multiparticle System
- •13.2 The Center of Mass
- •13.2.1 Example: Points on a Line
- •13.2.2 Example: Center of Mass of Object with Hole
- •13.2.3 Example: Center of Mass by Integration
- •13.2.4 Example: Center of Mass from Image Analysis
- •13.3.1 Example: Ballistic Motion with an Explosion
- •13.4 Motion in the Center of Mass System
- •13.5 Energy Partitioning
- •13.5.1 Example: Bouncing Dumbbell
- •13.6 Energy Principle for Multi-particle Systems
- •14 Rotational Motion
- •14.2 Angular Velocity
- •14.3 Angular Acceleration
- •14.3.1 Example: Oscillating Antenna
- •14.4 Comparing Linear and Rotational Motion
- •14.5 Solving for the Rotational Motion
- •14.5.1 Example: Revolutions of an Accelerating Disc
- •14.5.2 Example: Angular Velocities of Two Objects in Contact
- •14.6 Rotational Motion in Three Dimensions
- •14.6.1 Example: Velocity and Acceleration of a Conical Pendulum
- •15 Rotation of Rigid Bodies
- •15.1 Rigid Bodies
- •15.2 Kinetic Energy of a Rotating Rigid Body
- •15.3 Calculating the Moment of Inertia
- •15.3.1 Example: Moment of Inertia of Two-Particle System
- •15.3.2 Example: Moment of Inertia of a Plate
- •15.4 Conservation of Energy for Rigid Bodies
- •15.4.1 Example: Rotating Rod
- •15.5 Relating Rotational and Translational Motion
- •15.5.1 Example: Weight and Spinning Wheel
- •15.5.2 Example: Rolling Down a Hill
- •16 Dynamics of Rigid Bodies
- •16.2.1 Example: Torque and Vector Decomposition
- •16.2.2 Example: Pulling at a Wheel
- •16.2.3 Example: Blowing at a Pendulum
- •16.3 Rotational Motion Around a Moving Center of Mass
- •16.3.1 Example: Kicking a Ball
- •16.3.2 Example: Rolling down an Inclined Plane
- •16.3.3 Example: Bouncing Rod
- •16.4 Collisions and Conservation Laws
- •16.4.1 Example: Block on a Frictionless Table
- •16.4.2 Example: Changing Your Angular Velocity
- •16.4.3 Example: Conservation of Rotational Momentum
- •16.4.4 Example: Ballistic Pendulum
- •16.4.5 Example: Rotating Rod
- •16.5 General Rotational Motion
- •Index
Chapter 12
Momentum, Impulse, and Collisions
Two galaxies collide, leading to millions and millions of stars interacting. Can we say anything general about such a collision? For example, if you know the galaxies velocities after the collision, what can you learn about their velocities before the collision?
We have started to study the consequences of Newton’s laws of motion. Our first discovery is the conservation of mechanical energy. For an object subject only to conservative forces, the mechanical energy is conserved. Energy conservation provides a useful tool when solving problems in mechanics: we can relate the velocity and position of an object without having to find the position as a function of time. This is particularly useful when the interactions are complicated, and we have limited knowledge about the forces between objects. Actually, it allows us to reason about the behavior of a system without having force models, as long as we know that the forces are conservative.
Conservation of mechanical energy: The conservation of mechanical energy is an example of a conservation law, which we found by integrating Newton’s second law along the path:
t1
Fnet · vdt = K . |
(12.1) |
t0
For a one-dimensional motion where the net force only depends on the position, x , we get:
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Fxnetd x = K = |
2 mv12 − |
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(12.2) |
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If we could calculate the integral on the left, we could find the velocity as a function of position without finding the complete motion.
© Springer International Publishing Switzerland 2015 |
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A. Malthe-Sørenssen, Elementary Mechanics Using Python,
Undergraduate Lecture Notes in Physics, DOI 10.1007/978-3-319-19596-4_12
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12 Momentum, Impulse, and Collisions |
Conservation of momentuum: This techinque is sometimes called an integration method. To get energy conservation we integrated Newton’s second law over space. But we can also integrate Newton’s second law over time:
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madt = mv1 − mv0 . |
(12.3) |
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If the integral on the left is zero, that is, if the net force is zero, then we find that mv does not change. This gives us another conservation law: Conservation of momentum, mv. But how can that be useful? Didn’t we already know from Newton’s first law that if the net external force is zero, the velocity does not change? It turns out that conservation of momentum is not that useful for a single object, but it is very useful for systems consisting of several objects. For systems of several objects, we will demonstrate that the total momentum is conserved if there are no external forces acting on the system. It does not matter what internal forces are acting, the total momentum is conserved at all times as long as there are no external forces.
Collisions: Conservation of momentum is particularly useful for collisions. During a collision between two objects, the interactions between the objects can be very complicated, and may consist of both conservative and non-conservative forces, but as long as the objects are not affected by any external forces, their total momentum is conserved. We use this to find the velocities of each object after a collision from the velocities before a collision, without finding the motion of each object. Conservation of momentum is more general than the conservation of energy, since it is valid for any internal force, and not only for conservative forces.
Overview: In order to introduce these concepts, we will start by introducing tranlational momentum, p = mv. We reformulate Newton’s second law using momentum, and find that the integral of the net forces acting on an object corresponds to the change of momentum. We will then use these concepts to address systems with several objects, with a particular focus on collisions.
12.1 Motivating Example—Meteor Impact
You are now an expert solver of mechanics problems: Given a set of force models, you can find the motion of an object from Newton’s second law of motion using analytical or numerical tools. However, in some cases we may not know (or care to model) the detailed forces acting between two objects, but you still would like to know what happens to the objects. For example, you may observe a large meteor head directly towards a small planet. You know the masses and velocities of both
12.1 Motivating Example—Meteor Impact |
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Fig. 12.1 Illustration a collision between a meteor and a planet
Fon B from A
Fon A from B
objects at some time before the collision, and want to know the velocity of the planet after the hit. Can you do that without having a detailed model for the collision?1
Identify: The meteor impact is illustrated in Fig. 12.1. We describe the meteor (object A) with its position r A (t ) and its mass m A , and the motion of the planet (object B) with its position r B (t ) and its mass m B . At some time t0 before the impact you know the velocities of both objects, v A (t0) = v A,0 and vB (t0) = vB,0.
Model: You know you can find the motion of both objects by applying Newton’s second law to get an equation of motion. If we assume that the only interactions are between the planet and the meteor, Newton’s second law for objects A and B are:
FnetA |
= Ffrom B on A = m A a A |
(12.4) |
FnetB |
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= Ffrom A on B = m B aB |
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Unfortunately, we do not have a simple force model for the force from the meteor on the planet during the collision. How can we then solve the problem?
Using Newton’s third law: Fortunately, we can use a common trick: We know that the force from the meteor on the planet is the reaction force to the force from the planet on the meteor: Newton’s third law tells us that:
Ffrom A on B = −Ffrom B on A = F . |
(12.5) |
1A model for such a collision would be very complicated, as there are many different processes involved.
354 12 Momentum, Impulse, and Collisions
We can therefore rewrite Newton’s second law in (12.4) to be:
m A a A = −F |
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m B aB = F |
(12.6) |
which is valid as long as there are no other forces acting on the meteor or the planet. Now, we see that we can get rid of the unknown force, F, altogether by adding the two equations, getting:
m A a A + m B aB = −F + F = 0 . |
(12.7) |
Integration method: Now, we can integrate this equation, from the initial time t0, where we know the velocities, to the
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m A a A + m B aB dt = 0 , |
(12.8) |
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(12.9) |
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m A (v A (t1) − v A (t0)) + m B (vB (t1) − vB (t0)) = 0 . |
(12.10) |
Let us now group the quantities relating to t1 on the left side, and the quantities relating to t0 on the right side:
m A v A (t1) + m B vB (t1) = m A v A (t0) + m B vB (t0) . |
(12.11) |
This looks like what we have previously found for energy: It is a conservation law. But for what? For the quantity:
P = m A v A + m B vB , |
(12.12) |
which we call the total momentum of the system consisting of the planet and the meteor.
Solve: How can we use (12.11) to find the velocity of the planet and the meteor after the collision? First, we notice that (12.11) actually is valid for all times, also at any time during the collision. But it is not sufficient to find the velocities of each object after the collision. We only know what the awkward sum, m A v A + m B vB is after the collision. We do not know how this sum is distributed between the two objects. But since this is meteor impact we know something else, we know that the two objects move as one object after the collision: The meteor and the planet have the same velocity afterwards:
v A (t1) = vB (t1) = v1 . |
(12.13) |